When we start learning mathematics, the first thing we learn is
Numbers (0, 1, 2, 3, ...). Basically, numbers are a set of values used to represent different quantities. For example, we can represent the number of students in a class, the number of viewers watching the soccer world cup final etc.
The numbers we use most frequently are in
Decimal Number System. Similarly, there are other number systems which have different digits/characters to represent the quantities.
- Decimal Number System - 10 digits (0, 1, 2, 3, 4, 5, 6, 7, 8, 9)
- Binary Number System - 2 digits (0, 1)
- Octal Number System - 8 digits (0, 1, 2, 3, 4, 5, 6, 7)
- Hexadecimal Number System - 16 digits (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F)
You can learn more about the number systems
here.
Sometimes, it is required to convert decimal numbers to one of the other number systems and vice versa. Therefore, in this blog post, we will look into the different conversion mechanisms. Though there are different APIs in Java that does for you without any hassle but to grasp the concepts, it is imperative to look at how things work under the hood.
1a. Binary to Decimal conversion
/**
* This method accepts binary argument and convert it into decimal
*
* @param binary
* @return decimal equivalent
*/
private static int binaryToDecimal(int binary) {
// Decimal equivalent
int decimal = 0;
// The place determines the exponent of 2
int place = 0;
// Divide the number by 10 until true
while (true) {
if (binary == 0) {
break;
} else {
int temp = binary % 10;
// Decimal should be added to its previous value and the 2 raised to the power
// place
decimal += temp * Math.pow(2, place);
// Move to more significant digit
binary = binary / 10;
// Increment place for more significant digit
place++;
}
}
return decimal;
}
1b. Decimal to Binary conversion
/**
* This method converts decimal input to its binary equivalent
*
* @param decimal
*/
private static void decimalToBinary(int decimal) {
// Array that will store the binary digits
int[] binary = new int[40];
// This variable will store the index of each binary digit
int index = 0;
// Divide the decimal by 2 until possible
while (decimal > 0) {
// Remainders after dividing the decimal by 2 will be stored
binary[index++] = decimal % 2;
// Move forward
decimal = decimal / 2;
}
System.out.print("Decimal to Binary: ");
// Prints the binary digits in the reverse order
for (int i = index - 1; i >= 0; i--) {
System.out.print(binary[i]);
}
System.out.println("\n");
}
2a. Octal to Decimal conversion
/**
* This method converts octal number to its decimal equivalent
*
* @param octal
* @return decimal equivalent
*/
private static int octalToDecimal(int octal) {
// Decimal equivalent
int decimal = 0;
// The place determines the exponent of 8
int place = 0;
// Divide the number by 10 until true
while (true) {
if (octal == 0) {
break;
} else {
int temp = octal % 10;
// Decimal should be added to its previous value and the 8 raised to the power
// place
decimal += temp * Math.pow(8, place);
// Move to more significant digit
octal = octal / 10;
// Increment place for more significant digit
place++;
}
}
return decimal;
}
2b. Decimal to Octal conversion
/**
* This method converts decimal input to its binary equivalent
*
* @param decimal
*/
private static void decimalToOctal(int decimal) {
// Array that will store the binary digits
int[] octal = new int[40];
// This variable will store the index of each binary digit
int index = 0;
// Divide the decimal by 2 until possible
while (decimal > 0) {
// Remainders after dividing the decimal by 2 will be stored
octal[index++] = decimal % 8;
// Move forward
decimal = decimal / 8;
}
System.out.print("Decimal to Octal: ");
// Prints the binary digits in the reverse order
for (int i = index - 1; i >= 0; i--) {
System.out.print(octal[i]);
}
System.out.println("\n");
}
3a. Hexadecimal to Decimal conversion
/* This method converts hexadecimal to decimal equivalent
*
* @param hexadecimal
* @return decimal equivalent
*/
private static int hexadecimalToDecimal(String hexadecimal) {
// Allowed characters for a hexadecimal number
String characters = "0123456789ABCDEFG";
// Converting the input string to uppercase so that we can match them with the
// characters easily
hexadecimal = hexadecimal.toUpperCase();
// This variable will store the decimal representation of the hexadecimal value
int decimal = 0;
for (int i = 0; i < hexadecimal.length(); i++) {
// Get the character at the ith place in the input string
char c = hexadecimal.charAt(i);
// Get the place value of the character c
int n = characters.indexOf(c);
// Update the value of decimal
decimal = 16 * decimal + n;
}
return decimal;
}
3b. Decimal to Hexadecimal conversion
/**
* This method converts decimal to hexadecimal
* @param decimal
*/
private static void decimalToHexadecimal(int decimal) {
// Variable to store remainder
int remainder = 0;
// This variable will store hexadecimal equivalent
String hexadecimal = "";
// Characters in the Hexadecimal number system
char[] digits = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F' };
while (decimal > 0) {
// Get the remainder by dividing the number by 16
remainder = decimal % 16;
// Update the hexadecimal value by prepending with the allowed character at the
// position signified by the remainder
hexadecimal = digits[remainder] + hexadecimal;
// Move forward
decimal = decimal / 16;
}
System.out.print("Decimal to Hexadecimal: " + hexadecimal);
}
Conclusion
In this post, we have gone through the different methods of converting one number system to another without using any Java APIs. You can find the code of these examples on my
GitHub repository. Feel free to fork or open issues, if any.
I would love to hear your thoughts on this and would like to have suggestions from you to make it better. Feel free to befriend me on
Facebook,
Twitter or
Linked In or say Hi by
email.
Happy Coding 😊.
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